In an ap the sum of first n terms is 3n2/2
Webin an AP the sum of first n terms is 3n2/2 + 13n/2 Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions The first term of two APs are equal and the ratios of … WebUntitled - Free download as PDF File (.pdf), Text File (.txt) or read online for free.
In an ap the sum of first n terms is 3n2/2
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WebDefinition 1: A mathematical sequence in which the difference between two consecutive terms is always a constant and it is abbreviated as AP. Definition 2: An arithmetic sequence or progression is defined as a sequence of numbers in which for every pair of consecutive terms, the second number is obtained by adding a fixed number to the first one. WebWe know that the nth term of AP is given by the formula a n = a+ (n−1)d. ⇒ 50 = 5+ (n−1)3 50 = 5+3n−3 50 = 3n+2 48 = 3n 16 = n By using the sum of AP formula, S n = n/2 (a 1 +a n) S n = 16/2 (5+50) S n = 8 (55) S n = 440 …
WebJan 8, 2024 · Math Army 81.9K subscribers In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term. In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th... WebMar 8, 2024 · The sum of first n terms of an AP is +5n. To find: Which Term of AP is 152. The sum of first 20 terms . Explanation: The sum of first 20 terms .= +5n. = +5×20 = 3 × 400 + 100 = 1300 Which Term of AP is 152. = +5n. = 3×1+5×1 = 8 That is first number = 8 = +5n. = 3 × 2² +5×2 = 12+10 =22 = + 22 = 8+ = 22-8 = 14 Common difference = - = 14-8 = 6
WebIn an A.P., the sum of first n terms is 3n2 2 + 13 2n. Find its 25th term. Solution n term sum = 3n²/2 + 13n/2 as we know that nth term = (Sum of nth term ) - ( sum of (n-1)th term) … WebIn an A.P., the sum of its first n terms is 6n – n². Find is 25th term. CISCE ICSE Class 10. Question Papers 359. Textbook Solutions 25655. MCQ Online Mock Tests 6. Important Solutions 3382. Question Bank Solutions 25000. Concept Notes & …
WebApr 1, 2024 · One of the most important and exam oriented question from arithmetic progression chapter as it was already asked in previous year paper of 2006 in which we have been asked to find the nth term and the 25th term, if the sum of the first n terms of an AP is (3n^2/2 + 5n/2) Book- RS Aggarwal, Class 10, chapter 5C, question no 6(ii).
Web(11) Search the sum the first 20 terms of the numerical series in which 3 rl term is 7 also 7 in term is 2 more than three time its 3 rad term. Solution (12) Stylish an arithmetic series, which sum of first 11 conditions is 44 and one that of the next 11 terms is 55. inchelium language and culture associationWebMar 22, 2024 · Transcript. Ex 9.2,13 If the sum of n terms of an A.P. is 3n2 + 5n and its mth term is 164, find the value of m. Let a1, a2, … an be the given A.P Given, Sum of n terms = 3n2 + 5n Sn = 3n2 + 5n Putting n = 1 in (1) S1 = 3 × 12 + 5 × 1 = 3 × 1 + 5 × 1 = 3 + 5 = 8 Sum of first 1 terms = First term ∴ First term = a1 = S1 = 8 Sn = 3n2 + 5n …(1) Putting n = 2 in … income tax write offs listWebDec 19, 2024 · Example 5: Find the sum of first 30 terms of an A.P. whose second term is 2 and seventh term is 22. Solution. Let a be the first term and d be the common difference of the given A.P. Then, a 2 = 2 and a 7 = 22 ⇒ a + d = 2 and a + 6d = 22 Solving these two equations, we get inchelium language houseWebFind the rth term of the AP, the sum of whose first n terms is (3n2 + 2n). Given: The sum of first n terms. To Find: The rth term. Let the first term be a and common difference be d Put n = 1 to get the first term a = S1 = 3 + 2 = 5 Put n = 2 to get a + (a + d)2a + d = 12 + 4 = 1610 + d = 16d = 6tr = a + (r – 1)d inchelium newspaperWebApr 6, 2024 · AP 8 10 (1) 3130 (2) 3520 (3) 2790 (4) 1880 Sn 20 Σ Tn ทะ n S = 5 + 11 + 19 + 29 +41 + FL es es Σ = 0 + 5 + 11 + 0=5+6+ T = (5. Solution For sum of first 20 terms of the series: 5, 11, 19, 29, 41 ..... AP 8 10 (1) 3130 (2) 3520 (3) 2790 (4) 1880 Sn 20 Σ Tn ทะ n S = 5 + 11 + 19 . Solution For sum of first 20 terms of the series: 5, 11 ... inchelium pharmacyWebJul 21, 2024 · Explanation: Given that n th term of a series is. T n = 3n2 + 2n. hence, the sum Sn of given series up to first n terms. Sn = n ∑ n=1T n. = n ∑ n=1(3n2 +2n) = 3 n ∑ n=1n2 + 2 n ∑ n=1n. = 3 n 6 (n + 1)(2n + 1) +2 n 2 (n +1) = n 2 (n + 1)(2n + 1 + 2) inchelium highwayWebThe sum of the first n terms of an AP is (3n^2/2 + 5n/2). Find its nth term and the 25th term. asked Apr 15, 2024 in Arithmetic Progression by Vevek01 ( 47.4k points) income tax ww2